Jun 04, 2021

GRE is one of the most important exams to take for MBA and other higher studies. GRE comes with three sections: Quantitative reasoning, verbal reasoning, and analytical writing. GRE quant and verbal sections come with MCQs. Analytical writing section, on the other hand, holds descriptive question. **GRE** quant is all about math and GRE verbal is all about English skills.

GRE quant includes different types of math questions and it includes a diverse array of topics from Arithmetic, algebra, geometry, and data analysis. Candidates mostly focus on difficult problems for this section. However, arithmetic portion of GRE quant consists of a few answerable questions and these don’t take much time to solve. GRE quant questions on ratio and proportion are among the easiest questions of GRE. A little practice with these questions will help the candidates to secure a point here.

Here are some questions and the solutions:

**1. If the ratio of men to women at a party is 4:7, which of the following could be the number of people at the party?**

A. 50

B. 64

C. 66

D. 70

E. 78

It may seem that there is not enough information to answer this, but to answer a problem like this, you just need to add the coefficient x to each quantity and add: 4x+7x=11x.

Here is the solution:

The sum of the quantities is 11 and here, it represents a fraction of the entire number of party-goers, therefore, the answer has to be a multiple of 11.

Among the answer options, the only multiple of 11 in our choices is 66 (option C).

Or you can can test it in the following way:

If 11x=66, then x = 6.

4x= 4*6= 24 - the number of men

7x=7*6=42 - the number of women

**2. Find the combined ratio of (5 : 6), (7 : 9), (10 : 11).**

A. 56/157

B. 65/99

C. 21/31

D. 1/5

If we compound or compile two or more ratio, then, a : b and c : d, it will become ac:bd.

Therefore, the calculation as follows

(5 : 6), (7 : 9), (10 : 11) = 5/6 * 7/9 * 10/11 = 350/594

= 65/99 (option B)

**3. A mixture of sugar and water is in the ratio 3 : 2. A man adds 9 liters of water, and the mixture comes in the ratio of 3 : 5. Find the quantity of sugar in the new mixture.**

A. 9

B. 15

C. 12

D. 10

Let’s assume water is 2x, and sugar is 3x.

Given, 3x/2x+9 = 3/5

15x = 6x + 27

9x = 27

x = 3

Therefore, quantity of sugar = 3 * 3 = 9 liters (option A)

**4. Red, blue and yellow marbles in a bag have a ratio of 5 to 2 to 6. After removing the red marbles, there are 32 marbles left in the bag. How many red marbles were in the bag?**

(A) 4

(B) 8

(C) 20

(D) 24

(E) 52

Here, we need to use the total number of marbles along with the ratio of blue plus yellow.

blue + yellow = marbles left

2x + 6x = 32

8x = 32, so x = 4.

Make sure you’re answering the question being asked. Here, the wrong answer options include x = 4, 2x = 8 blue marbles, 6x = 24 yellow marbles, and 32 + 20 = 52 marbles originally in the bag. Now, you can use x = 4 and the original 5 : 2 : 6 ratio to find the number of red marbles.

5x = 5 × 4 = 20

There were 20 red marbles in the bag (Option C).

**5. Find the value of x. 35/84 = x/24**

(A) 8

(B) 10

(C) 25

(D) 26

(E) 30

35 × 24 = 84x Cross multiply.

x = 35 × 24 /84 Divide both sides by 84.

x = 35 × 24/84 = 7 × 5 × 2 × 2 × 6/2 × 6 × 7 = 10 Factor and cancel to simplify the calculations.

Therefore, x = 10 (option B).

**6. If 100 dollars can buy 0.07 grams of a rare radioactive material, how many grams can you buy with 106 dollars?**

(A) 7

(B) 70

(C) 700

(D) 7000

(E) 70,000

0.07/100 = g/106

0.07 × 106 = 100g Cross multiply.

g = (0.07 × 102 × 104)/100 = (7 × 104)/102= 7 × 102 Divide both sides by 100 and simplify.

g = 700 (option C).

These questions are comparatively easier than the other algebraic, geometric, and data analysis problems. These questions take less time and candidates can surely secure a whole point for these questions. They can get a **GRE tutor** to practice this - Contact MyPrivateTutor today and get expert GRE tutors.